this post was submitted on 06 May 2025
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Science Memes

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[–] Bonsoir@lemmy.ca 0 points 2 days ago (1 children)

There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices. Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.

[–] JayDee@lemmy.sdf.org 0 points 2 days ago (1 children)

If C is the correct choice, then that is only one answer out of four that is correct, meaning you only had a 25% chance to answer correctly. You've created a logical paradox.

25% occurs twice, so in reality there are only 3 outcomes from your pick. Since you know 25% is incorrect from this, that is 30% of the total answers, but also 50% of total options. Via this, you can conclude that both b and c are valid answers, depending on whether you view it in relation to outcomes or in relation to options. If you view the 3 outcomes, then you have a 60% chance of being right, but if you view the 4 options, you have a 50% chance of being right. Both 50% and 60% being accepted as anwswers solves the paradoxical nature of the question.

[–] shneancy@lemmy.world 0 points 2 days ago

the key word here is at random, you imagine a situation where you're doing it at random, but you're not actually answering randomly are you?

[–] samus12345@lemm.ee 0 points 2 days ago (1 children)

C, which means A or D, which means C, which means...

Lisa stays home?

[–] davidgro@lemmy.world 0 points 2 days ago

I asked Google to roll a D4 and it rolled a 4. So my answer (correct or not) when following the directions in the question is the fourth one (D).

[–] nialv7@lemmy.world 0 points 2 days ago (2 children)

The question is malformed and the correct answer isn't listed in the multiple choices. Therefore the correct answer is 0%

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[–] cholesterol@lemmy.world 0 points 2 days ago

Paradoxes aside, if you're given multiple choices without the guarantee that any of them are correct, you can't assign a chance of picking the right one at random anyway.

[–] thatradomguy@lemmy.world 0 points 2 days ago (1 children)

I see 25% twice so my bet is on 50%.

But 50% only appears once, which would make the answer 25%.

[–] xthexder@l.sw0.com 0 points 2 days ago (1 children)

It's probably graded by a computer, and a) or d) is a fake answer, since the automated system doesn't support multiple right answers.

I'm going to go with 25% chance if picking random, and a 50% chance if picking between a) and d).
If it's graded by a human, the correct answer is f) + u)

Many systems do allow multiple correct answers.

[–] OpenStars@piefed.social 0 points 2 days ago (2 children)
[–] BeMoreCareful@lemmy.world 0 points 2 days ago (2 children)
[–] ThatGuy46475@lemmy.world 0 points 2 days ago (1 children)
[–] LavaPlanet@lemm.ee 0 points 2 days ago (1 children)

Close, but nah, it's the meaning of life

[–] TimewornTraveler@lemm.ee 0 points 2 days ago* (last edited 2 days ago) (1 children)

nuh uh, it's the answer. to life, the universe, everything! Um, but what's the question?

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[–] TimewornTraveler@lemm.ee 0 points 2 days ago

how many roads must a man walk down?

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[–] qwet@lemm.ee 0 points 2 days ago (1 children)

This is a conundrum wrapped in a turducken, swaddled in nesting dolls.

[–] TimewornTraveler@lemm.ee 0 points 2 days ago (4 children)

lol chill out there buddy it is only self-referential once. maybe twice.

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[–] lmuel@sopuli.xyz 0 points 1 day ago (2 children)
[–] zkfcfbzr@lemmy.world 0 points 1 day ago* (last edited 1 day ago)

It is 33% if the answer itself is randomly chosen from 25%, 50%, and 60%. Then you have:

If the answer is 25%: A 1/2 chance of guessing right

If the answer is 50%: A 1/4 chance of guessing right

If the answer is 60%: A 1/4 chance of guessing right

And 1/3*1/2 + 1/3*1/4 + 1/3*1/4 = 1/3, or 33.333...% chance

If the answer is randomly chosen from A, B, C, and D (With A or D being picked meaning D or A are also good, so 25% has a 50% chance of being the answer) then your probability of being right changes to 37.5%.

This would hold up if the question were less purposely obtuse, like asking "What would be the probability of answering the following question correctly if guessing from A, B, C and D randomly, if its answer were also chosen from A, B, C and D at random?", with the choices being something like "A: A or D, B: B, C: C, D: A or D"

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[–] seeigel@feddit.org 0 points 1 day ago (1 children)

What's the correct value if the answer is not picked at random but the test takers can choose freely?

[–] chillhelm@lemmy.world 0 points 1 day ago

All answers are correct then.

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