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regex and awk... (programming.dev)

submitted 3 weeks ago by Corsair@programming.dev to c/linux@programming.dev

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Hi,

I would like to found a regex match in a stdout

stdout

 /dev/loop0: [2081]:64 (/a/path/to/afile.dat)

I would like to match

/dev\/loop\d/

and return /dev/loop0

but the \d seem not working with awk ... ?

How to achieve this ? ( awk is not mandatory )

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[–] unlawfulbooger@lemmy.blahaj.zone 4 points 3 weeks ago* (last edited 3 weeks ago)

You could try [0-9] instead?

awk '/\/dev\/loop[0-9]/ {print}'

If you have a larger sample of input and desired output, people can help you better.