this post was submitted on 27 Nov 2025
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Yep, all known to give wrong order of operations answers
Well, it's not me, so...
That's right. Welcome to programmers writing Maths apps without checking that they have their Maths right first. BTW, in some cases it's as bad as one of their calculators saying 2+3x4=20! 😂
To be clear, I am correct, because Distribution is part of the Brackets step, as we have already established...
Yes
No, you haven't finished solving the Brackets yet, which you must do before proceeding...
collapsed inline media
Nope! We have already established that you cannot remove the brackets if you haven't Distributed yet...
collapsed inline media
So what we actually get is...
2(8)²=(2x8)²=16²
and now that I have removed the Brackets, I can now do the exponent,,,
16²=256
Welcome to you finding the answer to 2x(3+5)² - where the 2 is separate to the brackets, separated from them by the multiply sign - rather than 2(3+5)², which has no multiply sign, and therefore the 2 must be Distributed
Then you're just a crank who lies to thirteen-year-olds about some bullshit you made up.
Both 2(8+0)^2^ and 2(8*1)^2^ simplify to 2(8)^2^. They can't get different answers.
Nobody but you has this problem. Real math doesn't work differently based on how you got there.
Weird then that's in in Maths textbooks isn't it 😂
Says another person who can't tell the difference between a(b+c) and a(bc) 🙄
Knowing how to read Maths textbooks is a problem?? 😂 I can assure you that all my students have this same "problem"
It does if you have different expressions, such as 8/2(1+3) and 8/2x(1+3)
B 8/2(1+3)=8/(2+6)=8/8
E
DM 8/8=1
AS
B 8/2x(1+3)=8/2x4
E
DM 8/2x4=4x4=16
AS
Different expressions, different order of evaluation, same rules of Maths (both following BEDMAS here) resulting in the different evaluations of the different expressions 🙄
If you can simplify before distributing - and the PDFs you spam say you can - then there is no difference. You made it the fuck up.
2(n)^2^ is 2n^2^ whether n=a+b or n=a*b=ab. If you want to square the 2, that's (2n)^2^.
It's not about the multiply sign, or grouping, or division. You fooled yourself into saying 2=1.