this post was submitted on 27 Nov 2025
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Then you're just a crank who lies to thirteen-year-olds about some bullshit you made up.
Both 2(8+0)^2^ and 2(8*1)^2^ simplify to 2(8)^2^. They can't get different answers.
Nobody but you has this problem. Real math doesn't work differently based on how you got there.
Weird then that's in in Maths textbooks isn't it 😂
Says another person who can't tell the difference between a(b+c) and a(bc) 🙄
Knowing how to read Maths textbooks is a problem?? 😂 I can assure you that all my students have this same "problem"
It does if you have different expressions, such as 8/2(1+3) and 8/2x(1+3)
B 8/2(1+3)=8/(2+6)=8/8
E
DM 8/8=1
AS
B 8/2x(1+3)=8/2x4
E
DM 8/2x4=4x4=16
AS
Different expressions, different order of evaluation, same rules of Maths (both following BEDMAS here) resulting in the different evaluations of the different expressions 🙄
If you can simplify before distributing - and the PDFs you spam say you can - then there is no difference. You made it the fuck up.
2(n)^2^ is 2n^2^ whether n=a+b or n=a*b=ab. If you want to square the 2, that's (2n)^2^.
It's not about the multiply sign, or grouping, or division. You fooled yourself into saying 2=1.