this post was submitted on 22 Dec 2025
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... only one choice is a triangle.
How is this difficult, other than if you are shape blind?
The correct choice is B.
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick B, while B does have elements in common with A and C...
(it shares 'red' with A, and 'solid color fill' with C)
... it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
B is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
What a fool you are!
... only one choice is an outline.
How is this difficult, other than if you are line blind?
The correct choice is A.
If you pick B, A is also red, and C is also a filled solid. So B is not unlike either A or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick A, while A does have elements in common with B and C...
(it shares 'red' with B, and '4-gon' with C)
... it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
A is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
Welp.
I tap out, you're right lol.
Don't attempt set theory before breakfast, otherwise you end up making a fool of yourself as I have.
=[
Hangry is not a useful state to approach logic from.