this post was submitted on 27 Nov 2025
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Please find a Maths textbook that backs that up as being the correct answer. i.e. Exponents before Brackets. Should be easy, no? 🤣
Nobody has argued exponents should go before brackets.
I'm saying distribution being mandatory is an invented rule from your part.
No wonder you can't produce such a simple request. I thought you had calculators that work "correctly"?
You did! 😂 You said 2(3+5)²=2(8)²=2(64), which is doing the Exponent when there are still unsolved Brackets 😂
You still haven't explained how it's in 19th Century textbooks if I "made it up"! 😂
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If you don't remember Roman Numerals either, that's 1898
says person who still hasn't produced a single textbook that supports anything that they say, and it's such a simple request 😂
Solving brackets does not include forced distribution. Juxtaposition means multiplication, and as such,
2(3+5)²is the same as2*(3+5)², so once the brackets result in8, they're solved.Distribution needs to happen if you want to remove the brackets while there are still multiple terms inside, but it's still a part of the multiplication. You can't do it if there is an exponent, which has higher priority.
Your whole argument hangs on the misinterpretation of textbooks. This is what it feels like to argue against Bible fanatics lmao.
Tell you what, provide me a solver that says
2(3+5)²is 256 and you've won, it's so easy no?Yes it does! 😂
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No, it doesn't. A Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms...
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No it isn't. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms
They don't - you still have an undistributed coefficient, 2(8)
Not until you've Distributed and Simplified they aren't
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if you want to remove the brackets, YES, that's what the Brackets step is for, duh! 😂 The textbook above says to Distribute first, then Simplify.
As in 2(8)=(2x8) and 2(3+5)=(6+10) is multiple Terms inside 😂
Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed
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It doesn't have a higher priority than Brackets! 🤣
says person who can't cite any textbooks that agree with them, so their whole argument hangs on all Maths textbooks are wrong but can't say why, 😂 wrongly calls Products "Multiplication", and claimed that I invented a rule that is in an 1898 textbook! 🤣 And has also failed to come up with any alterative "interpretations" of "must" and "Brackets" that don't mean, you know, must and brackets 😂
says the Bible fanatic, who in this case can't even show me what it says in The Bible (Maths textbooks) that agrees with them 😂
provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣
And in the meantime, here's one saying it's 1, because x(x-1) is a single Term...
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https://youtu.be/xoZzHMoB5qA
This is a college textbook, and that explains how to solve it.
Another example: https://stemjock.com/STEM%20Books/OpenStax%20CA%202e/Chapter%201/Section%201/OSCACh1s1e32.pdf
Alternatively, here is another example: https://www.kingphilip.org/wp-content/uploads/2021/07/Supplemental_Topics_from_Algebra_1.pdf
In case you can't find the correct part:
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It's a college refresher course on high school Maths. They also forgot to cover The Distributive Law, which is not unusual given college Professors don't actually teach high school Maths.
From the same refresher course 🙄
Which also doesn't cover The Distributive Law, which isn't surprising given that chapter isn't even about order of operations! 😂
Still not about a(b+c). You lot are investing so much effort into such an obvious False Equivalence argument it's hilarious! 😂
Don't move the goalposts. I've posted textbooks showing that "solving brackets" only applies to the inside, and distribution is part of multiplication and optional.
You've said yourself your magic rule is taught in highschool, so a refresher course in college would never ignore it.
Now instead of giving weak excuses, provide your part of the proof. And I'm not talking about multiplication, I want to see anywhere where a distribution is given precedence over an exponent.
If 5(4)^2^ is 5*16 then 2(8)^2^ is 2*64.
I get a free hoagie.
I didn't. You're the one who has been desperately trying to make a False Equivalence argument between a(b+c) and a(bc)² 🙄
No you haven't. A college refresher isn't a Maths textbook, and I already pointed out to you that they don't mention The Distributive Law at all, unlike, you know, high school Maths textbooks 🙄
And the high school Maths textbooks I posted prove you are wrong about that 🙄
And the high school Maths textbooks I posted prove you are wrong about that too, 🙄 unless you think "optional" is a valid interpretation of what "must" means 😂
Yep
And yet you proved that they did in fact forget about it 🙄
they say to person who has been backed up by every textbook they posted so far 😂
Just scroll back dude - they're all still there, like here for example.
Well that'll be a nice change then 😂
Because you are hell bent on making a False Equivalence argument between a(b+c) and a(bc)². I don't care dude. there is no exponent in the meme. I'll take that as an admission that you are wrong about a(b+c) then.
Who are you talking to?
All I said was: If 5(4)^2^ is 5*16, like this college math textbook shows, then 2(8)^2^ is 2*64.
Every published example will agree this is how it works. None, at any level of education, will agree with your bullshit.