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Indeed, usually you would want to avoid a notation of
sqrt(-1)
or(-1)^(1/2)
. You would usee^(1/2 log(-1))
instead because mathematicians have already decided on a "natural" way to define the logarithm of complex numbers. The problem here lies with choosing a branch of the logarithm ase^z = x
has infinitely many complex solutionsz
. Mathematicians have already decided on a default branch of the logarithm you would usually use. This matters because depending on the branch you choosesqrt(-1)
either givesi
or-i
. A square-root is usually defined to only give the positive solution (if it had multiple values it wouldn't fit the definition of a function anymore) but on the complex plane there isn't really a "positive" direction. You would have to choose that first to make suresqrt
is defined as a function and you do that via the logarithm branch.So, just writing
sqrt(-1)
leaves ambiguity as you could either define it to givei
or-i
but writinge^(1/2 log(-1))
then everyone would just assume you use the default logarithm branch and the solution isi
.