this post was submitted on 14 Jul 2025
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[–] Chrobin@discuss.tchncs.de 0 points 17 hours ago (1 children)

I'd say the $\int dx$ is the operator and the integrand is the operand.

[–] Zagorath@aussie.zone 0 points 16 hours ago

You're misunderstanding the post. Yes, the reality of maths is that the integral is an operator. But the post talks about how "dx can be treated as an [operand]". And this is true, in many (but not all) circumstances.

∫(dy/dx)dx = ∫dy = y

Or the chain rule:

(dz/dy)(dy/dx) = dz/dx

In both of these cases, dx or dy behave like operands, since we can "cancel" them through division. This isn't rigorous maths, but it's a frequently-useful shorthand.